Ransom Note — LeetCode
на канале: Benabub
Step-by-step algorithm visualization for LeetCode #383 (Ransom Note). The solution employs a frequency array (hash map equivalent) to store character counts from the magazine string. By mapping characters 'a'-'z' to indices 0-25, the algorithm efficiently verifies if the magazine contains enough occurrences of each letter to construct the ransom note, terminating early if a character is missing.
Complexity Analysis:
Time Complexity: O(m + n) — where m is the length of the magazine and n is the length of the note. Both strings are traversed linearly.
Space Complexity: O(1) — the fixed-size integer array of length 26 occupies constant space regardless of input size.
Timestamps:
0:07 — Character Frequency Mapping
2:03 — Note Validation & Count Decrement
2:57 — Final Result
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