php - SQL Comment in CodeIgniter Active Record? - Stack Overflow
Опубликовано: 13 Май 2026
на канале: ResponseXAI
на канале: ResponseXAI
0
Kudos to Darrrrrren for getting me on the right track.
I defined a variable in my controller like this:
$this->sqlStamp = ' /* Executed by ' .strtoupper( $this->router->class .'->' .$this->ro
#since #where('1=1' #track #ınserts #this
https://stackoverflow.com/questions/1...
https://stackoverflow.com/questions/1...