LeetCode 3195: Find the Minimum Area to Cover All Ones I | C# Solution | Grid Traversal
Welcome to the channel! In this video, we'll walk through a clear and efficient C# solution for LeetCode 3195: Find the Minimum Area to Cover All Ones I. We'll break down the logic of finding the smallest bounding box that covers all the ones in a 2D grid. #leetcode #csharp #codinginterview #problemsolving
Optimal Solution:
Time Complexity: O(m * n)
Space Complexity: O(1)
▶️ Chapters:
00:00 - Understanding problem statement
00:46 - Understanding the approach
05:01 - Big O Notation
05:33 - C# solution walk-through
06:31 - Solution analysis - runtime + memory
06:39 - Conclusion
📝 Key Concepts & Algorithms:
2D Grid / Matrix Traversal
Bounding Box Calculation
Finding Minimum & Maximum Coordinates
Edge Case Handling (Grid with no ones)
💡 Main Learning Points:
An efficient method to find the extremities (min/max row and column) of elements in a matrix.
How to calculate area from bounding box coordinates.
A foundational approach that can be applied to many other grid-based problems.
🎯 Target Audience:
Developers preparing for technical coding interviews.
C# programmers looking to enhance their algorithmic problem-solving skills.
Students and professionals learning about algorithms on 2D data structures.
✅ Prerequisites:
Basic knowledge of C# syntax and data types.
Familiarity with 2D arrays (matrices) in C#.
🔗 Links:
LeetCode Problem: https://leetcode.com/problems/find-th...
Solution Code: https://leetcode.com/problems/find-th...
📚 Related LeetCode Problems:
221. Maximal Square
85. Maximal Rectangle
939. Minimum Area Rectangle
850. Rectangle Area II
⭐ Additional Tips to Emphasize:
1. Initialize your boundary variables carefully. A robust method is to set `min_row` and `min_col` to `int.MaxValue` and `max_row` and `max_col` to `int.MinValue`.
2. Always consider the edge case where the grid contains no '1's. The loop to find boundaries won't update the initial values, so you need a final check to return 0.
3. The area calculation is `(max_row - min_row + 1) * (max_col - min_col + 1)`. The `+1` is crucial because the dimensions are inclusive of the start and end indices.
Thanks for watching! If this video helped you, please hit the like button, subscribe for more content, and share your questions or alternative solutions in the comments below. I read and respond to all of them! #softwareengineering #developer #codingskills