LeetCode 81: Search in Rotated Sorted Array II | Binary Search Explained
In this video, we solve *LeetCode 81 – Search in Rotated Sorted Array II* using an efficient Binary Search approach with duplicate handling.
This is a tricky interview problem that combines rotated arrays, searching logic, and edge case management.
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💡 *What You’ll Learn*
• How Binary Search works on rotated arrays
• Handling duplicates correctly
• Identifying sorted halves efficiently
• Step-by-step dry run of the algorithm
• Time & Space Complexity explained clearly
---
🧠 *Concepts Covered*
• Arrays
• Binary Search
• Rotated Sorted Arrays
• Duplicate handling
• Edge case optimization
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📌 *Problem Summary*
Given a rotated sorted array that may contain duplicates, determine whether a target element exists in the array.
Return true if found, otherwise return false.
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⚡ *Approach Used in This Video*
We use Binary Search to reduce the search space efficiently.
Key observations:
• If the middle element matches the target → return true
• If duplicates block decision-making, shrink the search space from both ends
• Identify which half is sorted
• Decide whether the target lies inside that sorted half
This allows efficient searching even in rotated arrays with duplicates.
---
⏱ *Complexity*
Average Time Complexity: O(log n)
Worst Case Time Complexity: O(n) due to duplicates
Space Complexity: O(1)
---
🎯 *Why This Matters*
This problem helps you:
• Master advanced Binary Search patterns
• Handle difficult edge cases confidently
• Improve interview problem-solving skills
---
🔗 *Connect With Me*
GitHub: https://github.com/Ritesh007-max
Twitter (X): https://x.com/RiteshGabale007
LinkedIn: / ritesh-gabale-59a2b5365
Portfolio: https://ritesh-portfolio-v06.netlify....
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📈 *Tags*
#leetcode #dsa #binarysearch #rotatedarray #codinginterview #programming #arrays
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👍 Like & Subscribe for daily LeetCode problem-solving videos.
🚀 *LeetCode 81: Search in Rotated Sorted Array II | Binary Search Explained*
In this video, we solve *LeetCode 81 – Search in Rotated Sorted Array II* using an efficient Binary Search approach with duplicate handling.
This is a tricky interview problem that combines rotated arrays, searching logic, and edge case management.
---
💡 *What You’ll Learn*
• How Binary Search works on rotated arrays
• Handling duplicates correctly
• Identifying sorted halves efficiently
• Step-by-step dry run of the algorithm
• Time & Space Complexity explained clearly
---
🧠 *Concepts Covered*
• Arrays
• Binary Search
• Rotated Sorted Arrays
• Duplicate handling
• Edge case optimization
---
📌 *Problem Summary*
Given a rotated sorted array that may contain duplicates, determine whether a target element exists in the array.
Return true if found, otherwise return false.
---
⚡ *Approach Used in This Video*
We use Binary Search to reduce the search space efficiently.
Key observations:
• If the middle element matches the target → return true
• If duplicates block decision-making, shrink the search space from both ends
• Identify which half is sorted
• Decide whether the target lies inside that sorted half
This allows efficient searching even in rotated arrays with duplicates.
---
⏱ *Complexity*
Average Time Complexity: O(log n)
Worst Case Time Complexity: O(n) due to duplicates
Space Complexity: O(1)
---
🎯 *Why This Matters*
This problem helps you:
• Master advanced Binary Search patterns
• Handle difficult edge cases confidently
• Improve interview problem-solving skills
---
🔗 *Connect With Me*
GitHub: https://github.com/Ritesh007-max
Twitter (X): https://x.com/RiteshGabale007
LinkedIn: / ritesh-gabale-59a2b5365
Portfolio: https://ritesh-portfolio-v06.netlify....
---
📈 *Tags*
#leetcode #dsa #binarysearch #rotatedarray #codinginterview #programming #arrays
---
👍 Like & Subscribe for daily LeetCode problem-solving videos.