The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that the processing delay is negligible, the minimum number of bits for the sequence number field in a frame for maximum utilization, when the sliding window protocol is used, is:
A) ⌈log(2LtR+2K)/K⌉
B) ⌈log(2LtR)/K⌉
C) ⌈log(2LtR+K)/K⌉
D) ⌈log(2LtR+2K)/2K⌉