Hybridisation & structure of xenon compounds. ( p block -12 - 18 group elements)
XeOF2
The geometry of XeOF2 is consistent with a trigonal bipyramidal, AX2YE2, VSEPR arrangement that gives rise to a T-shaped geometry in which the two free valence electron lone pairs and Xe-O bond domain occupy the trigonal plane and the Xe-F bond domains are trans to one another and perpendicular to the trigonal plane.
xef6
XeF6 has seven electron pairs. It consists of 6 bond pairs and one lone pair.Xenon has 8 electrons in its valance shell and it forms six bonds with the fluorine atoms.When the fluorides of xenon have formed the electrons in the valence shell of xenon get unpaired and are promoted to vacant 5d orbitals.
xeof4
Structure of .To draw the Lewis dot structure, the number of valence electrons present in the compound must be calculated.Accordingly number of valence electrons present in is as follows:
Valence electrons
= Xe + O + 4(F)
= 8+6+4(7)
= 14+28
= 42
Thus has 42 valence electrons. These electrons must be allotted to the elements in such a way that each elements attain octet.In the given case, Xenon is exceptional as it can expand octet.Thus the structure of comes out to be the structure which is given in the attachment.