Discrete Time Convolution || Example 2.4 || S&S 2.1.2(2)(English) (Oppenheim)

Опубликовано: 18 Октябрь 2024
на канале: Electrical Engineering Academy
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S&S 2.1.2(2)(English) (Oppenheim) || Example 2.4.

In this video we discuss techniques for solving discrete time convolution problem with the help of example 2.4

Example 2.4: As a further example, consider the two sequences
[ ] { 1, 0 :::; n :::; 4 x n = 0, otherwise
and
h[n] = { a 11, 0 :::; n .:::; 6.
0, otherwise
These signals are depicted in Figure 2.8 for a positive value of a greater than 1. In order to calculate the convolution of the two signals, it is convenient to consider five separate intervals for n. This is illustrated in Figure 2.9.