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Video Description : ✅How To Find Size of Column?
📌GIVEN DATA
Axial Load (P) = 750 kN
Factored Load (Pu) = 1.5 x 750 = 1125 kN
M25 = fck = 25 N/mm²
Fe415 = fy = 415N/mm²
📌Axial Load (IS 456:2000)
◼️Pu= 0.4 x fck x Ac + 0.67 x fy x Asc
Assume, Asc as 1% on Ag
Area Of Steel In Concrete (Asc)
Gross Area Of Column (Ag)
📌Calculation
1125 x 10³ = 0.4 x 25 (0.99 Ag) + 0.67 x 415 x 0.01Ag
1125 x 10³ = 12.68 Ag
📌Gross Area
Ag = (1125 x 10³) / 12.68
Ag = 88722 mm²
📌Size Of Column
Ag = 88722 mm²
Ag = B²
B = √Ag
B = √88722
B = 300 x 300mm
Asc = 0.01Ag
Asc = 0.01 X 88722
Asc = 887mm²
Assume 16mm dia bar 6No’s
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