LED GLOW
In this video we glowing a led, here we are using one led, one 330k resistor and dc power supply of 5v.Connect one end of resistor to button and button another to power supply and another terminal of resistor with the led ,remaining end of led is connected to ground.
Here, the supply voltage is 5V, LED Forward Voltage (VF) is 2.2 Volt and Forward Current (IF) is 10mA.
Now the Value of resistor (which we will connect in Series with LED) for this circuit would be:
Resistor Value = ((Vsupply-Vf))/If = (5 -2.2) / 10mA = 280Ω
Resistor Power rating formula for this circuit
Resistor Power Rating = IF2x Resistor Value= (10mA) 2 x 280 Ω = 0.028W = 28mW
But This is the minimum required resistor value to ensure that resistor will not overheat, so its recommended that to double the power rating of resistor that you have calculated, therefore, choose 0.028W x 2 = 0.056W = 56mW resistor for this circuit.
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JJD - Adventure [NCS Release]
Different Heaven (NCS)
this music is provided by NCS, the link to the track is
https://www.youtube.com/watch?v=f2xGx...
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Proteus File or Circuit Download
http://www.mediafire.com/file/yik890r...
http://www.mediafire.com/file/wweh61w...
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Please watch: "Lifi Communication by Arduino UNO Download Project"
• Lifi Communication by Arduino UNO Dow...
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