A Gardner wants to construct a rectangular bed | Case Study Maxima Minima Application of Derivatives
a gardener wants to construct a rectangular bed of garden in a circular patch of land solution
He takes the maximum perimeter of the rectangular region as possible. (Refer to the images given below for calculations)
The perimeter of rectangle P is:
1) a. 4x+4√/a2-x2
b. x+a2-2
c. 4x+ Va² 22
d. +4a²-x2
ii.) To find critical points put
iii.) Value of y is
a. a/2
b. a/√2
c. 2a
d. √2a
iv.) P is maximum when the rectangle is square
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