(2 of many to come) We take the Laplace Transform of f(t) = e^t using the definition, then look at using a shortcut with L{dy/dt} = s L{y} + y(0). This allows us to easily show that the Laplace Transform of e^(at) is 1/(s-a). We finish with a quick example solving the exponential growth differential equation with the Laplace Transform.
Video 1: • Laplace Transforms 1: definition and prope...
Video 3: • Laplace Transforms 3: The Laplace transfor...
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