Problem - https://www.geeksforgeeks.org/problem...
Given a binary string s. Perform r iterations on string s, where in each iteration 0 becomes 01 and 1 becomes 10. Find the nth character (considering 0 based indexing) of the string after performing these r iterations (see examples for better understanding).
Example 1:
Input:
s = "1100"
r = 2
n = 3
Output:
1
Explanation:
After 1st iteration s becomes "10100101".
After 2nd iteration s becomes "1001100101100110".
Now, we can clearly see that the character at 3rd index is 1, and so the output.
Example 2:
Input:
s = "1010"
r = 1
n = 2
Output:
0
Explanation :
After 1st iteration s becomes "10011001".
Now, we can clearly see that the character at 2nd index is 0, and so the output