LeetCode 19 | Remove Nth Node from End of List | Algorithm Explained (Java)w

Опубликовано: 04 Октябрь 2024
на канале: Xavier Elon
539
15

Running Time: O(N)
Space Complexity: O(1)

The description reads:
"Given a linked list, remove the n-th node from the end of list and return its head.

Example:

Given linked list: 1-2-3-4-5, and n = 2.

After removing the second node from the end, the linked list becomes 1-2-3-5.
Note:

Given n will always be valid.

Follow up:

Could you do this in one pass?"

Always be pluggin:
Github: https://github.com/xavierelon1
Github HackerRank Solutions: https://github.com/XavierElon1/Hacker...
Github Leetcode Solutions: https://github.com/XavierElon1/LeetCo...
Facebook:   / xavier.hollingsworth.3  
Instagram:   / xavierelon  
LinkedIn:   / xavier-hollingsworth-524144127  
Twitter:   / elon_xavier