LeetCode | Remove Nth Node From End 🔗
By keeping one pointer n steps ahead, we can locate the node to remove in one pass
🔹 Approach: Two Pointers
🔹 Key idea: Maintain n-step gap between pointers
🔹 Time Complexity: O(n)
🔹 Space Complexity: O(1)
Daily DSA practice to improve problem-solving skills 🚀
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