LeetCode 69 Sqrt(x) in Python | Easy Coding Tutorial for Beginners
Solve LeetCode 69 "Sqrt(x)" in Python with this beginner-friendly coding tutorial! This problem asks you to find the integer square root of a non-negative integer `x` (e.g., for x = 8, return 2 since 2² = 4 ≤ 8 and 3² = 9 {greater than} 8). We’ll use Python’s exponentiation operator to compute the square root and convert it to an integer in one line. Perfect for Python learners, coding beginners, or anyone prepping for coding interviews!
🔍 *What You'll Learn:*
Understanding LeetCode 69’s requirements
Using Python’s exponentiation to compute the square root
Converting the result to an integer with truncation
Testing with example cases
💻 *Code Used in This Video:*
class Solution(object):
def mySqrt(self, x):
"""
:type x: int
:rtype: int
"""
return int(x ** 0.5)
Test cases
solution = Solution()
Test case 1: Perfect square
print(solution.mySqrt(4)) # Output: 2
4 ** 0.5 = 2.0, int(2.0) = 2
Test case 2: Non-perfect square
print(solution.mySqrt(8)) # Output: 2
8 ** 0.5 ≈ 2.828, int(2.828) = 2
Test case 3: Zero
print(solution.mySqrt(0)) # Output: 0
0 ** 0.5 = 0.0, int(0.0) = 0
Test case 4: Large number
print(solution.mySqrt(16)) # Output: 4
16 ** 0.5 = 4.0, int(4.0) = 4
🌟 *Why Solve LeetCode 69?*
This problem is a great introduction to mathematical operations in coding, a common topic in interviews! We’ll show how `int(x ** 0.5)` computes the integer square root by taking the square root of `x` and truncating the decimal part. The time complexity is O(1) since it’s a single mathematical operation, and the space complexity is O(1). Note: While this solution works, a follow-up might ask for a binary search approach to avoid using built-in functions—perfect for learning optimization! Master this, and you’ll be ready for more advanced LeetCode challenges!
📚 *Who’s This For?*
Python beginners learning coding
Coding enthusiasts tackling LeetCode problems
Developers prepping for technical interviews
👍 Like, subscribe, and comment: What LeetCode problem should we solve next? Next up: LeetCode math problems—stay tuned!
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