What if gravity were proportional to 1/r³ instead of 1/r²? | Physics Simulations
Two simulations of the three-body problem. The forces between the masses in the simulation on the left are proportional to (1/r²)(2/(1 + e^(-3 * (r/20)^(4))) - 1) (a smoothed 1/r² function). The forces between the masses in the simulation on the right are proportional to 1/(r³ + ε³) (a smoothed 1/r³ function), where ε = 20. In both simulations, all three masses have the same starting positions and velocities.
all masses equal
symmetric start
chaos / chaotic motion
velocities and positions calculated using Runge-Kutta methods
25fps, 90s
#Physics #PhysicsSimulations #ThreeBodyProblem #Gravity
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