In this video, I solved important examples of Exercise 2.4. These questions are important long questions. In exercise 2.4, the chain rule is primarily used. In this exercise, we solve derivatives of parametric functions and implicit functions differentiation. In Parametric functions, both x and y are dependent variables and a third variable t is called an independent variable. The third variable t is called a parameter.
In the previous lectures, I explained the examples of Exercise 2.4 using chain rule by making a suitable substitution and derivatives of parametric functions
To understand the concept of the chain rule, watch;
Lecture 11:
• Chain Rule Concept | Chapter 2 | FSc Part ...
To understand how to find derivatives of a parametric function, watch;
Lecture 13:
• Derivatives of Parametric functions | Exer...
To understand, how to find derivatives of function using suitable substitution, watch;
Lecture 12:
• Examples related chain rule (using suitabl...
Last 2 Questions of Exercise 2.3, visit;
Lecture 10:
• Exercise 2.3 (Part 4) Question#16 and 17 |...
For the Question#14 & 15 of Exercise 2.3, visit;
Lecture 9:
• Exercise 2.3 (Part 3) Question#14 & 15 | F...
For the first 9 questions of Exercise 2.3, visit;
Lecture 7:
• Exercise 2.3 (Part 1) Question#1 to 9 | FS...
To understand the concept of Quotient Rule, visit;
Lecture 6:
• Quotient Rule of Derivatives | Exercise 2....
To understand the concept of Product Rule, visit;
Lecture 5:
• Product Rule of Derivative | Chapter 2 Mat...
To understand the concept of power rule, visit;
Lecture 4:
• Basic Derivative Rules: | Power Rule and i...
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