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This is the 69th Video of our Playlist "Strings : Popular Interview Problems" by codestorywithMIK
Today we will be solving a problem based on strings and reverse simulation - Process String with Special Operations II | Simplified | Dry Runs | Leetcode 3614 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Process String with Special Operations II | Simplified | Dry Runs | Leetcode 3614 | codestorywithMIK
Company Tags : Will update later
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Intervie...
Leetcode Link : https://leetcode.com/problems/process...
My DP Concepts Playlist : • Roadmap for DP | How to Start DP ? | Topic...
My Graph Concepts Playlist : • Graph Concepts & Qns - 1 : Graph will no m...
My Segment Tree Concepts Playlist : • Segment Tree | Introduction | Basics | Bui...
My Recursion Concepts Playlist : • Introduction | Recursion Concepts And Ques...
Trie Playlist - • Word Search II | Leetcode 212 | Detailed |...
Difference Array Technique: Concepts & Qns : • Introduction | What | How | Difference Arr...
Top K from Sorted Structures Pattern : • Introduction | Top K from Sorted Structure...
Binary Lifting : • Introduction | Binary Lifting | DP On Tree...
My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Intervie...
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Video Summary :
The intuition here is that you don't need to actually build the final string to find one character; you just need to track how its length L evolves through each operation. So first you sweep left to right, simulating only the length as each symbol (* removes, # doubles, % reverses, letters appends) changes it. Once you know the total length, you walk back from the end and "undo" each operation, remapping your target index k to where it would have lived in the shorter, pre-operation string. When k lines up exactly with the position a letter added (k == L), that letter is your answer.
✨ Timelines✨
00:00 Introduction
00:08 Motivation
00:19 Problem Explanation
02:55 Normal Case
04:48 Handling #
16:30 Handling english characters
30:30 Handling %
37:21 Handling *
42:51 Story Points
44:25 Coding it up
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