Find Minimum in Rotated Sorted Array II | LeetCode 154
In this video, we solve LeetCode 154: Find Minimum in Rotated Sorted Array II, a classic Binary Search interview problem that becomes tricky because the array contains duplicates.
At first glance, the problem looks similar to the standard rotated array minimum problem — but duplicates completely change the edge cases and decision making.
💡 Core Idea:
We are given a sorted array that has been rotated multiple times.
Our task is to find the minimum element while minimizing the number of operations.
The challenge comes when:
✔ Left, mid, and right values become equal
✔ Binary search conditions become ambiguous
✔ Duplicates break the normal sorted-half logic
🚀 What’s covered in this video:
✅ Problem statement with examples
✅ Understanding rotated sorted arrays
✅ Why duplicates make this harder
✅ Binary Search intuition
✅ Edge case handling
✅ Step-by-step dry run
✅ Optimized approach explanation
✅ Clean and interview-ready code walkthrough
🧠 Key Insight:
Normally in rotated arrays:
👉 One half is always sorted
But with duplicates:
👉 nums[mid] == nums[right] creates uncertainty
So we carefully shrink the search space while preserving the minimum element.
🎯 Why this problem is important:
Very common in coding interviews
Strengthens Binary Search concepts
Improves edge case handling
Helps understand modified Binary Search patterns
Frequently asked in Google, Amazon, Meta interviews
🔥 What you’ll learn:
Modified Binary Search
Rotated array techniques
Handling duplicates efficiently
Search space reduction strategies
Writing optimized interview-quality solutions
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