Java 8 Stream API Interview Questions: Partition Numbers into Even and Odd from List using Java 8
Q9. How to Partition Numbers into Even and Odd using Stream API Java 8
Welcome to Learn Code With Saurabh! In this video, you will learn: Java program demonstrates how to use Java 8 Streams to perform conditional filtering on collections.
Explanation of the code:
This Java program demonstrates how to partition a list of integers into even and odd numbers using Java Streams and the partitioningBy() collector.
Here's an explanation:
1. Input Data: A list of integers (numbers) from 1 to 10 is defined.
2. Partitioning:
o The numbers.stream() creates a stream from the list.
o Collectors.partitioningBy(n n % 2 == 0) divides the integers into two groups based on whether they are even or odd. It returns a Map where the key is a Boolean:
o true for even numbers.
o false for odd numbers.
3. Output:
o The even numbers are retrieved using partitioned.get(true), and the odd numbers are retrieved using partitioned.get(false).
o The program then prints the even and odd numbers separately.
Example Output:
• Even numbers: [2, 4, 6, 8, 10]
• Odd numbers: [1, 3, 5, 7, 9]
Source Code: https://github.com/learncodewithsaura...
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