Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once. The relative order of the elements should be kept the same. Then return the number of unique elements in nums.
EXPLANATION CODE:
1) This Java code is the solution to remove duplicates from an array of integers nums.
2) The removeDuplicates method takes the array as input and returns the length of the modified array with duplicates removed.
3) First, the code checks if the input array is null or empty. If so, it immediately returns 0 since there are no elements to remove duplicates from.
4) Following that, the code initialises two variables: index and check.
5) The index variable keeps track of the current position where non-duplicate elements should be placed in the modified array. It starts at 0 since the first element in the original array is always considered non-duplicate.
6) The check variable is used to iterate through the remaining elements in the array to check for duplicates. It starts at 1 since the comparison begins with the second element.
7) The code compares the elements at nums[check] and nums[index] inside the while loop. If they vary, it indicates the discovery of a new non-duplicate element.
8) In such a scenario, the non-duplicate element is positioned at nums[index] by assigning nums[check] to it, moving the index up to the next position in the modified array.
9) The check variable is increased to advance to the following element in the initial array whether or not a duplicate was discovered.
10) After iterating through all the elements, the method returns index + 1, which represents the length of the modified array with duplicates removed.
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Contents:
0:00 - Reading
2:13 - Solving
3:49 - Explaining