We solved this using Binary Search in O(log n) time complexity. If you have any questions please do let me know.
Basically we need to find first and last indexes of given target in input and return those, else we ca return -1, -1.
Input: nums = [5,7,7,8,8,10], target = 8
Output: [3,4]
Input: nums = [], target = 0
Output: [-1,-1]
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