Python Daily Question - 117
Python Daily Question - 117
Explanation:-
1. Outer Loop (i):
The outer loop iterates over the numbers from 2 to 3 (range(2, 4)), inclusive.
In the first iteration, i will be 2, and in the second iteration, i will be 3.
2. Inner Loop (j):
The inner loop also iterates over the numbers from 2 to 3 (range(2, 4)), inclusive.
During each iteration of the outer loop, the inner loop runs completely.
3. Condition:
In each iteration of the inner loop, it checks if i is not divisible by j.
If i is not divisible by j (i.e., i % j != 0), it means j is not a factor of i.
4. Counting:
If the condition i % j != 0 is satisfied, it means i is not divisible by j, so the counter variable a is incremented by 1.
Iterations:
1. First Iteration (i = 2):
Inner Loop (j):
j = 2: 2 % 2 != 0 (False), so no increment.
j = 3: 2 % 3 != 0 (True), so a is incremented by 1.
a becomes 1.
2. Second Iteration (i = 3):
Inner Loop (j):
j = 2: 3 % 2 != 0 (True), so a is incremented by 1.
j = 3: 3 % 3 != 0 (False), so no increment.
a becomes 2.
Final Output:
The final value of a after both iterations is 2.
So, The Final Answer = 2.
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