Python Daily Question - 126
Explanation:
1. Initialization:
a = 1
The variable a is initialized to 1.
2. Outer Loop:
for i in range(2, 6):
The outer loop runs with i taking values from 2 to 5 (inclusive).
3. Inner Loop:
for j in range(2, 5):
The inner loop runs with j taking values from 2 to 4 (inclusive).
4. Update a:
a = a + (i - j)
For each combination of i and j, the value of a is updated by adding (i - j).
Iteration Details:
Let's go through each iteration step-by-step:
Initial value of a: a = 1
First outer loop (i = 2):
j = 2: a = a + (2 - 2) = 1 + 0 = 1
j = 3: a = a + (2 - 3) = 1 + (-1) = 0
j = 4: a = a + (2 - 4) = 0 + (-2) = -2
Second outer loop (i = 3):
j = 2: a = a + (3 - 2) = -2 + 1 = -1
j = 3: a = a + (3 - 3) = -1 + 0 = -1
j = 4: a = a + (3 - 4) = -1 + (-1) = -2
Third outer loop (i = 4):
j = 2: a = a + (4 - 2) = -2 + 2 = 0
j = 3: a = a + (4 - 3) = 0 + 1 = 1
j = 4: a = a + (4 - 4) = 1 + 0 = 1
Fourth outer loop (i = 5):
j = 2: a = a + (5 - 2) = 1 + 3 = 4
j = 3: a = a + (5 - 3) = 4 + 2 = 6
j = 4: a = a + (5 - 4) = 6 + 1 = 7
Final Value:
After all iterations, the final value of a is 7.
So, The Final Answer = 7
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