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Arithmetic Progressions(AP)
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Chapterwise CBSE PYQs Sets -X
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Q23 | Which term of the AP -11/2 , -3, -1/2 , …. is 49/2 ?
Given the AP is -11/2, -3, -1/2, ....
To find the term which is equal to 49/2,
we can use the formula for the nth term of an AP:
an = a + (n-1)d
Where a is the first term, n is the term we want to find, and d is the common difference.
We know that the given term is 49/2,
so we can set that equal to an
an = 49/2
a + (n-1)d = 49/2
We also know that a = -11/2 and d = 5/2.
So we can substitute these values into the equation:
-11/2 + (n-1)(5/2)=49/2
Solving for n gives:
n = 13
So, the 13th term of the arithmetic progression -11/2 , -3, -1/2 , …. is 49/2 .