bash: complete: -I: invalid option
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I'm using the bash complete -I option as follows:
__cmp_exec() {
local curr="$2"
case "$curr" in
./*)
local selected=$(find "." ! -type d -executable | fzf --query "$curr")
if [[ -n "$selected" ]]; then
COMPREPLY=( "$selected" )
else
COMPREPLY=()
fi
esac
}
complete -I -F __cmp_exec -o bashdefault
__cmp_exec() {
local curr="$2"
case "$curr" in
./*)
local selected=$(find "." ! -type d -executable | fzf --query "$curr")
if [[ -n "$selected" ]]; then
COMPREPLY=( "$selected" )
else
COMPREPLY=()
fi
esac
}
complete -I -F __cmp_exec -o bashdefault
Locally everything works. But when I use the script on our server I get an error:
bash: complete: -I: invalid option
bash: complete: -I: invalid option
This is the bash version I'm running:
$ bash --version
bash --version
GNU bash, version 4.4.20(1)-release (x86_64-redhat-linux-gnu)
Copyright (C) 2016 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later http://gnu.org/licenses/gpl.html
This is free software; you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
history -a
$ bash --version
bash --version
GNU bash, version 4.4.20(1)-release (x86_64-redhat-linux-gnu)
Copyright (C) 2016 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later http://gnu.org/licenses/gpl.html
This is free software; you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
history -a
I thought bash supports the -I flag from version 4.0, am I wrong in assuming so?
Tags: bash,debianSource of the question:
https://stackoverflow.com/questions/7...
Question and source license information:
https://meta.stackexchange.com/help/l...
https://stackoverflow.com/Source of the question:
https://stackoverflow.com/questions/7...
Question and source license information:
https://meta.stackexchange.com/help/l...
https://stackoverflow.com/