Question -
2a² - 3ab + 4bc, 6ab - a² - 5bc and 13bc - 8a² + ab.
Solution -
= (2a² - a² - 8a²) + (-3ab + 6ab + ab) + (4bc - 5bc + 13bc)
= (-6a² - a²) + (3ab + ab) + (-1bc + 13bc)
Answer -
-7a² + 4ab + 12bc
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By - Alora.