LeetCode Daily: Maximum Number of Points with Cost Solution in Java | August 17, 2024
🔍 LeetCode Problem of the Day: Maximum Number of Points with Cost
Today, we're tackling the "Maximum Number of Points with Cost" problem in Java, as part of the LeetCode daily challenge series. This problem involves maximizing points in a matrix while accounting for a specific cost when moving between columns.
👉 Problem Link: https://leetcode.com/problems/maximum...
👉 Solution: Pinned on the comments
🌟 Problem Description:
In this challenge, you are given a 2D matrix points where each element represents the points you can collect. The task is to determine the maximum points you can collect while moving from the first row to the last, with the condition that moving between different columns incurs a cost.
🔑 Code Explanation:
Initialization: We initialize a dp array to store the maximum points we can collect up to the current row.
Row Iteration: For each row in the matrix, we calculate two auxiliary arrays, left and right, which help us efficiently compute the maximum points while considering the cost of moving between columns.
Left Array: Tracks the maximum points considering movements to the left.
Right Array: Tracks the maximum points considering movements to the right.
Update dp: For each column, the dp array is updated by adding the current row's points to the maximum value between the left and right arrays.
Final Result: After iterating through all rows, the maximum value in the dp array represents the maximum points that can be collected.
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