JEE Adv 2020 Paper 2 Continuity and Differentiability (Hindi)
This video covers a highly challenging problem on Continuity and Differentiability and gives a method to solve it in less than 2 minute with the help of graphs, which would otherwise take a very long time to solve. This is taken from recently held JEE Advanced 2020 Paper II question number 5 and the question is
Let the functions f: (−1, 1) → R and g: (−1, 1) → (−1, 1) be defined by f(x) = |2x − 1| + |2x + 1| and g(x) = x − [x], where [x] denotes the greatest integer less than or equal to x. Let f ∘ g: (−1, 1) → R be the composite function defined by (f ∘ g)(x) = f(g(x)). Suppose c is the number of points in the interval (−1, 1) at which f ∘ g is NOT continuous, and suppose d is the number of points in the interval (−1, 1) at which f ∘ g is NOT differentiable. Then the value of c + d is ___________
This video is suitable for the students aspiring for engineering entrance exam and is also suitable for CBSE, ISC, HSC, IB Board students and the students who have genuine interest in learning geometry
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