y = 3cos(pi*t) | 2nd derivative and acceleration Exam Question | Math Methods Unit 3 and 4 |

Опубликовано: 03 Август 2026
на канале: Be Bright
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This motion video shows how to find the velocity and acceleration from the position function. The function is a trigonometric function y = 3cos(pi*t) and shows how to use the unit circle and exact values to find the time when the velocity is 0m/s and the acceleration when the velocity is 0m/s.

It requires us to find the first derivative and the 2nd derivative to solve this complex familiar unfamiliar question.



Easy steps, worked solution for a math exam question. Math Methods Unit 3 & 4 QCAA VCE
#mathmethods #calculus #derivative #motion #mathmethods #applicationofdifferentiation #unit4 #differentiation #trigonometry
Differentiation trigonometry