To compare bond angles we need to
determine the number of bond pair and lone pair around central atom via dot-cross diagram
deduce its shape using VSEPR concept
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Learn how to use VSEPR to deduce shapes of molecules here at https://chemistryguru.com.sg/valence-...
A. ICl3
Central atom (I) has 3 bond pairs and 2 lone pairs.
Shape is T-shape, bond angle 86 degrees.
B. SF3+
Central atom (S) has 3 bond pairs and 1 lone pair.
Shape is trigonal pyramidal, bond angle 107 degrees.
C. ClO3-
Central atom (Cl) has 3 bond pairs and 1 lone pair.
Shape is trigonal pyramidal, bond angle 107 degrees.
D. N2H4
Central atom (N) has 3 bond pairs and 1 lone pair.
Shape is trigonal pyramidal, bond angle 107 degrees.
Therefore the answer to this question is option A.
Topic: Chemical Bonding, Physical Chemistry, A Level Chemistry, Singapore
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