Real Analysis | Solutions - 2.3.1 | sup(f+g) ≤ sup(f) + sup(g)
In this video:
1. We show that if f and g are bounded above, then (f+g) is bounded above.
2. We show that sup(f+g) ≤ sup(f) + sup(g).
3. We give an example where the strict inequality occurs.