If you can find an error, then state the error - I show you that you are wrong.
If you write garbage, the I will delete your comment and block you. Resist the urge to be your moronic, ignorant selves.
I know that stupidity cannot be cured, but ignorance can! Try removing head from butt in order to get a less smelly perspective. You're welcome morons!!!
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Proving a bijection is possible between real numbers and N:
Assuming a decimal tree, I can assign a unique integer to each node as follows:
0-9 in the first column.
0-99 in the second column.
0-999 in the third column.
0.3 would therefore be assign the value 3.
0.01 would be assigned the value 22 (10+10+1+1).
0.004 would be assigned the value 155 (10+100+40+1+1+1+1+1).
Therefore, the unique label 3-22-155 can be written as a unique integer 322155.
So, I can find 322155 by traversing the decimal tree.
Conversely, I can also find 0.314 by searching for the label 3-22-155.
Therefore, I have a bijection. Your objection might be that I can't do this for an infinite decimal expansion, but my retort is that neither can you! For however many digits you give me, I can return a number. Since you can't complete infinity, you can't say that I should be able to.
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